How many joules are needed to raise 50 grams of iron from 55oC to 200oC? The specific heat capacity of iron is 0.46 J/goC.

Answer 1

q = m c ΔT

q = ?

m = 50 g

c = 0.46 J / g°C

ΔT = Tf - Ti = 200 - 50 = 150 °C

q = 50 g x 0.46 J / g°C x 150 °C = 3450 J

NOTE! Based on the significant figures of the given values in your question, q should be rounded down to 3000 J (1 sig fig).