How many liters of water vapor can be produced from 26 mol O2 at STP?

Question

The equation is: 2H2(g)+O2(g)=2H2O(g)

Answer 1

From the balanced chemical reaction, 1 mole of O₂ reacts to form 2 moles of H₂O. This gives a mole ratio of 1:2. Use the mole ratio to first convert mol O₂ to mol H₂O.

26 mol O₂ x (2 mol H₂O / 1 mol O₂) = 52 mol H₂O

At STP, 1 mole of an ideal gas will occupy a volume 22.4 L.

L of H₂O = 52 mol x (22.4 L / 1 mol) = 1164.8 L ~ 1200 L (rounded to 2 significant figures)