Anthony T. answered 04/22/21
Patient Science Tutor
How to prepare 100mL of 5% solution of nitric acid (70%) - d = 1.42 ?
A 5% solution of HNO3 would have 5 grams of HNO3 in 100 mL of a solution. As concentrated HNO3 is 70% by mass, the mass of the 70% solution required is 0.70 M = 5g where M is the mass of concentrated solution needed, or M = 7.14 g. The volume of 7.14 g of concentrated HNO3 can be obtained from the density V = 7.14 g / 1.42 = 5.03 mL.
If you then measure 5.03 mL of the concentrated HNO3 and dilute to 100 mL with water, you would have the required 5% solution.
Note: This assumes the 5% solution is mass/volume %.