Calculate the [H3O+1] if [OH-1]= 1.41 x 10-7 M

Question

a. 1.41 x 10^-7 M

b. 7.09 x 10^-8 M

c. 1.41 x 10^-8 M

d. 1.00 x 10^-7 M

e. 1.00 x 10^-14 M

Answer 1

Kw = [H₃O⁺] [OH^-]

1.00 x 10^-14 = [H₃O⁺] x 1.41 x 10^-7

[H₃O⁺] = 1.00 x 10^-14 / 1.41 x 10^-7 = 7.09 x 10^-8 M (answer choice b)