ASAP answer please with all steps

Question

ASAP answer please with all steps

To make a buffered solution of HX and NaX with a pH of 6.11, what mass of NaX (MM 130.5 g/mol) must be added to 250.0 mL of a 1.0 M solution of HX?

Ka of HX is 1.72 x 10-6.

Answer 1

pH=pKa+log([A-]/[HX])

6.11=-log(1.72*10^-6)+log(x)

x=2.216

This is the ratio of [X-]/[HX]

Find mol HX from 250.0 mL of a 1.0 M

0.250L(1mol/L)=0.250 mol HX

2.216=^{(mol X-)}/_{(mol HX)}

2.216=x/0.250

x=0.554 mol X-

use molar mass: mass of NaX (MM 130.5 g/mol)

0.554 mol X- = 0.554 mol NaX

0.554 mol NaX (130.5 g/mol)=72.297 g NaX