Joel L. answered 04/20/21
Tutor
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MS Mathematics coursework with 20+ Years of Teaching Experience.
∫(√𝑎 - √𝑥)2 𝑑𝑥
= ∫(𝑎 - 2√(𝑎𝑥) +𝑥) 𝑑𝑥
= 𝑎 ∫𝑑𝑥 -2√𝑎 ∫√𝑥 𝑑𝑥 + ∫𝑥𝑑𝑥
= 𝑎𝑥 -2√𝑎 • (2/3) 𝑥 3/2 +(1/2) 𝑥2 + C
= 𝑎𝑥 -(4/3)√𝑎•𝑥 3/2 +(1/2) 𝑥2 + C