Squares Adder. Write a program that reads in a number (integer) indicating how many values you are to read.

Question

Write a program that reads in a number (integer) indicating how many values you are to read. Then read in that many more numbers (all integers) and output the sum of their squares.

Input of 4 1 2 3 4 would mean "Read in 4 numbers" - the 1 2 3 and 4. Read each one in and add its square to the total. 1+4+9+16 would mean an output of 30

Hint: Steps to a solution:

1. First read in the first input (how many more numbers there are and count from 1 to that value. The first test should count to 4, the second test count to 2, the third test count to 6.
2. Then instead of just counting - try to read in that many inputs and print them back out. Basically print all of the inputs except the first. (First test should print 1 2 3 4, second 5 10, third 2 4 8 16 32 64
3. Then print each number squared
4. Now you can worry about summing the squares

Code:

#include <iostream>

using namespace std;

int main()

{

//YOUR_CODE

}

Answer 1

using namespace std;

#include <iostream>

int main()

{

int n=-1;

while (n<1)

{

cout << "How many? :>";

cin >> n;

}

long sum=0;

for (int iLoop=0; iLoop<n; iLoop++)

{

int iNum;

cout << "input the # :>";

cin >> iNum;

sum = sum + iNum*iNum;

}

cout << sum << endl;

}

Answer 2

This is a pretty common procedure to obtain input, and there are multiple ways to do this in C++. One way is to use std::cin. If performance is a concern, you can add std::ios::sync_with_stdio(false); prior to reading your input. (Some reasons for this performance improvement detailed https://www.geeksforgeeks.org/cincout-vs-scanfprintf/)

Example reading input:

#include <iostream>

#include <math.h>

using namespace std;

int main() {

int n;

int sum = 0;

// Get standard input

cin >> n;

for (int i = 0; i < n; i++){

int next;

cin >> next;

sum += pow(next, 2);

}

cout << sum << endl;

}