Counting 2. Read in three numbers. A start value, an increment value, and an end value (all integers). Start counting from the start, adding the increment at each step...

Question

Read in three numbers. A start value, an increment value, and an end value (all integers). Start counting from the start, adding the increment at each step, until you are at or above the end value.

Input of 4 3 12 means start from 4, count by 3's until you hit (or go past) 12. Your program should output: 471013 (4 7 10 13 without any spaces).

Hint: this problem is MUCH easier to do if you think of the last value (or first) as a special case that happens after the loop

Code:

#include <iostream>

using namespace std;

int main()

{

//YOUR_CODE

}

Answer 1

using namespace std;

#include <iostream>

int main()

{

int iStart;

int iStop;

int iIncr;

cout << "Input start value :>";

cin >> iStart;

cout << "Input stop value :>";

cin >> iStop;

cout << "Input increment value :>";

cin >> iIncr;

if ((iStart<iStop && iIncr>0) || (iStop>iStart && iIncr<0))

{

for (int iLoop=iStart; iLoop<=iStop; iLoop+=iIncr)

{

cout <<iLoop;

}

}

}