Cell Labeler. In a spreadsheet, the rows are numbered and the columns are lettered, like this:

Question

In a spreadsheet, the rows are numbered and the columns are lettered, like this:

ABC
1	A1	B1	C1
2	A2	B2	C2

The code below reads in a number of rows and columns. Prints out the cells that would be in a grid of that size (do not worry about the column/row headers). For example something with 3 columns and 2 rows and should be displayed like:

A1 B1 C1

A2 B2 C2

You should print a space after every "cell", even the last one in each row. If spaces were changed to _ your output should look like:

A1_B1_C1_

A2_B2_C2_

Hint: Start by printing just the column and row as numbers:

11 21 31

12 22 32

Then you can worry about printing the column as a letter. Remember that to change a number into a letter you can add it to 'A' and store the result as a char.

char temp = x - 1 + 'A'; //temp will be 'A' if x is 1, 'B' if x is 2...

Code:

#include <iostream>

using namespace std;

int main()

{

int columns, rows;

cin >> columns >> rows;

//YOUR_CODE

}

Answer 1

using namespace std;

#include <iostream>

int main()

{

int numRows=-1;

int numColumns=-1;

while (numRows<1 && numColumns<1)

{

cout << "Please input # of rows :>";

cin >> numRows;

cout << "Please input # of columns :>";

cin >> numColumns;

if (numColumns>26)

{

cout << "too many - sorry " << endl;

numColumns=-1;

}

}

char startChar='A';

char stopChar = startChar+numColumns;

for (int iRowLoop=0; iRowLoop<numRows; iRowLoop++)

{

for (char chColumn=startChar; chColumn<=stopChar; chColumn++)

{

cout << chColumn << (iRowLoop+1) << " ";

}

cout << endl;

}

}