Sidney P. answered • 04/20/21
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(5.00g H2) * (1 mol H2 /2.016g H2) * (2 mol NH3 /3 mol H2) * (17.02g NH3 /1 mol NH3) = 28.3g NH3.
Jayla L.
asked • 04/19/21Find the mass of ammonia (NH3) produced when 5.00 g of hydrogen gas reacts with an excess of nitrogen gas. N2(g) +3H2(g) = 2NH3(g)
Find the mass of ammonia (NH3) produced when 5.00 g of hydrogen gas reacts with an excess of nitrogen gas. N2(g) +3H2(g) = 2NH3(g)
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