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Question

What mass of water can be heated from 3.1°C to 34.6°C by the addition of 3,851.2 of energy? Please provide your final answer rounded to two decimal places and provide the proper units, in their respective boxes. (Hint: You have the specific heat (c) of water in your notes!)

Answer 1

Hi, Camila,

Check another response I gave to a different question, The basics are better explained there.

The formula that relates energy, specific heat, mass, and temperature change is:

q = mCDT

where q is energy, m is a unit denoting some aspect of mass (g, kg, mole, etc.) and DT is the temperature change (T₂ - T₁)=DT. c is the specific heat of the substance in question. Let the mass be X, the unknown here.

3851.2J = X*(4.184J/gK)*(31.5K)

X = 29.2 grams

Bob