So my question is based on chemistry

Question

What is the mass in grams of 3.04 mol of ammonia vapor, NH3?

Answer 1

First you need to find the molecular weight of each element within the compound. For NH₃ the elements are N and H, which have molecular weights of 14.007 g/mol and 1.008 g/mol respectively. Now you add up the molecular weight of the compound as a whole. Since there are 3 H's in NH₃ you have to multiple the molecular weight of H by 3 (1.0008 X 3 = 3.024 g/mo)l. Now that you have found the total weight of the 3 hydrogens you can add them to the weight of nitrogen (3.024 g/mol H₃ + 14.007 g/mol N = 17.031 g/mol NH₃). You have the g/mol of NH₃ but now you need just the mass for a sample of 3.04 mols, so you need to set up an equation to cancel out the mols such as this: 3.04 mol (17.031 g/mol) = ? the mols cancel each other out leaving you with the mass 3.04 mol (17.031 g/mol) = 51.774 g NH₃.