Consider the following balanced equation: C3H8(g) + 5O2(g)  3CO2(g) + 4H2O(l)

Question

a. How many moles of C3H8 would react with 7.93 moles of oxygen?

b. How many moles of H2O could be produced from 18.9 moles of C3H8?

c. If 19.00 grams of O2 are mixed with excess C3H8 how many grams of CO2 could be produced?

Answer 1

It's all dimensional analysis:

a) (7.93 mol O₂) * (1 mol C₃H₈ /5 mol O₂) = 1.59 mol C₃H₈.

b) (18.9 mol C₃H₈) * (4 mol H₂O /1 mol C₃H₈) = 75.6 mol H₂O.

c) (19.00g O₂) * (1 mol O₂ /32.00g O₂) * (3 mol CO₂ /5 mol O₂) * (44.00g CO₂ /1 mol CO₂) = 15.68g CO₂.