How many grams of potassium chloride are needed to prepare 500 mL of a 0.5 M solution?

Answer 1

Hello Vanessa, I'd be happy to help you with your question!

How many grams of potassium chloride are needed to prepare 500 mL of a 0.5 M solution?

Molarity = moles of solute

liters of solution

First find the moles of potassium chloride (KCl).

0.5 M KCl = x moles KCl

0.500 L

0.5 M(0.500 L) = 0.25 moles KCl

Now convert moles to grams. Look up the masses of K and Cl on the periodic table and add them to find the molar mass.

K = 39.098 g/mol

Cl = 35.453 g/mol

39.098 + 35.453 = 74.551 g/mol

Now multiply to find the grams of KCl.

0.25 mol KCl x 74.551 g KCl = 18.638 g KCl

mol KCl

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