A 3.6 g sample of iron (III) oxide reacts with sufficient aluminum to be entirely used up. How much iron is produced?

Answer 1

Write the balanced reaction: Fe₂O₃ + 2 Al --> Al₂O₃ + 2 Fe. Then stoichiometry is (3.6g Fe₂O₃) * (1 mol Fe₂O₃ /159.7g Fe₂O₃ ) * (2 mol Fe /1 mol Fe₂O₃) * (55.845g Fe /1 mol Fe) = 2.52g Fe.