A gas has a volume of 2.8 L at a temperature of 27°C. What temperature in degrees celsius is needed to expand the volume to 15 L?

Answer 1

At constant pressure, V₂ / V₁ = T₂ / T₁ and T₂ = T₁ V₂ / V₁ = (27 +273 K) (15 L) / (2.8 L) = 1607 K = 1334 °C.