If 5.91 g of CuNO3 is dissolved in water to make a 0.900M solution, what is the volume of the solution in milliliters?

Answer 1

Hello Caitlyn, I'd be happy to help you solve this problem!

The equation for Molarity is as follows:

Molarity = moles of solute

liters of solution

First you must find the number of moles of the solute. To calculate moles first find the molar mass of the solute by using the atomic mass of the elements from the periodic table.

Cu = 63.546

N = 14.0067

O = 15.999

CuNO₃ has 1 atom of Cu, 1 atom of N, and 3 atoms of oxygen.

1(63.546) + 1(14.0067) + 3(15.999) = 63.546 + 14.0067 + 47.997 = 125.55 g/mol

If there are 5.91 g of CuNO₃:

5.91 g CuNO₃ x mol CuNO₃ = 0.47 mol CuNO₃

125.55 g CuNO₃

Use 0.47 mol CuNO₃ for "moles of solute", 0.900 M for Molarity, and x for the liters of solution. Solve for x

0.900 M = 0.47 mol CuNO₃

x

0.900x = 0.47 mol

0.900 0.900

x = 0.5222 L

Convert this to mL for your final answer.

0.5222 L x 1000 mL = 522.2 mL

1 L

If you have any further questions please feel free to send me a message or comment!