calculate the volume(in liters) occupied by 42.56g of CO at 0.992 atm pressure and a temperature of 65 degrees Celsius

Answer 1

First find the number of moles of CO: (42.56g CO) * (1 mol CO /28.01g CO) = 1.519 mol CO.

From the ideal gas law, V = nRT/P = (1.519 mol) * (0.08206 L atm/mol K) * (65 + 273.15K) / (0.992 atm) = 42.51 L of CO.