Sidney P. answered 04/16/21
Astronomy, Physics, Chemistry, and Math Tutor
The 20.0g C7H6O3 * (1 mol C7H6O3 /138.0g C7H6O3 ) * (2 mol C9H8O4 /2 mol C7H6O3 ) = 0.1449 mol C9H8O4 .
The 20.0g C4H6O3 * (1 mol C4H6O3 /102.0g C4H6O3 ) * (2 mol C9H8O4 /1 mol C4H6O3 ) = 0.3920 mol C9H8O4 . So C7H6O3 is the winner because some of the other chemical remains when this is consumed.
The theoretical yield is (0.1449 mol C9H8O4 ) * (180.1g C9H8O4 /1 mol C9H8O4 ) = 26.09g C9H8O4 .
The percent yield is 100 * actual / theoretical = 100 * (22.03/26.09) = 84.44%.