
Bradford T. answered 04/15/21
Retired Engineer / Upper level math instructor
a) f'(x) = (3e3x-3e-3x)/3 = e3x-e-3x
f'(1) = e3 - e-3
b) f'(x) = e-1/(x+1)(1/(x+1)2)
f'(0) = e-1/4
c)h'(z) = 2z(1+e-z)+z2(-e-z)
h'(-1) = 2(-1)(1+e) -e-1 = -2-2e-e = -2-3e
Sammy K.
Thank you!04/15/21
Sammy K.
Hello, thank you so much but would you mind showing all the steps or explaining what you did exactly? That would be very helpful.04/15/21