In the first one you need to use both the product rule and the chain rule.
In the second one: use the power rule and the chain rule as follows
2 sin (x3-2x+4)(3x2-2)
There is no cos in the 2nd answer...the answer I wrote is complete.
In the first one you got messed up:
3(x+4)2(x-6)6+6(x-3)5(x+4)3 which you can simply a bit by taking out common factors....but I will leave that to you.
Sammy K.
For the 1. a) would the answer be 6(x-3)^5 (x+4)^3 + 3(x-3)^6 (x+4)^2 or 3(x-3)^5 (x+4)^2 (3x+5)? I'm not too sure, I'm a little confused. And for b) would it be 2(3x^2-2)cos(x^3-2x+4)sin(x^3-2x+4) or (6x^2-4)cos(x^3-2x+4)sin(x^3-2x+4)?04/14/21