Hello Lindsay, I'd be happy to help you answer this question!

**2KClO3 --> 2KCl + 3O2**

Both sides of the reaction are balanced, because there is the same number of both elements on the product and reactant side of the reaction. Therefore the coefficients will provide the ratio. For every 3 moles of O_{2} that are produced there are 2 moles of KClO_{3} that decompose . Therefore the ratio is 3 to 2. Starting with 18.0 moles of KClO_{3} you will get:

18.0 ~~mol KClO~~_{3} x __ 3 mol O___{2}__ __ = 27.0 mol O_{2}

2 ~~mol KClO~~_{3}

Your answer is 27.0 mol O_{2}

Lindsey O.

Thank you so much! Do you mind answering a few other questions?04/13/21