What mass of ammonia can be made from 10.0 mol H2?

Question

The equation is: N2(g)+3H(g)=2NH3

Answer 1

The first step is to look at the equation and make sure it's balanced.

N₂ + 3H₂ = 2NH₃

There are 2 N atoms and 6 H atoms on each side, so it is already balanced. Looking at the coefficients, for every 3 moles of H₂ there are 2 moles of NH₃ produced. Apply that ratio to get the moles for NH₃.

10.0 mol H₂ x 2 mol NH₃ = 6.67 mol NH₃

3 mol H₂

Now the moles of NH₃ produced are known, but the question is asking what mass of NH₃ can be made from 10.0 mol of H₂. The next step is to use the periodic table to calculate the molar mass of NH₃. Looking those up, you will find that:

H = 1.008 g/mol N = 14.007 g/mol

The molar mass of NH₃ is equal to 3H + 1N.

3(1.008) g/mol + 1(14.007) g/mol = 3.024 + 14.007 = 17.031 g/mol

Now multiply the moles of NH₃ by the atomic mass to get your final answer in grams.

6.67 mol NH₃ x 17.031 g = 113.60 grams NH₃

mol

The moles unit cancels out and you're left with the final answer of 113.60 grams NH₃