Passcode Checker. Users of a system are supposed to pick a 3 character pass code such that there is at least one character that is a digit (number) and one character that is not a letter or number.

Question

Users of a system are supposed to pick a 3 character pass code such that there is at least one character that is a digit (number) and one character that is not a letter or number. Something like "A7*" or "45!" or "$2C". The digit and the special symbol may be any of the three characters.

Write a program that reads in three characters and prints YES if they meet the criteria and NO if they do not.

Hints:

1. Remember cctype has functions for isalpha, isdigit, and ispunct. Check the documentation here.
2. Also remember that ! is NOT. You can express the idea "x is not a digit character" with:

!isdigit(x)

Code:

#include <iostream>

You probably want the char type library...

using namespace std;

int main()

{

//YOUR_CODE

}

Answer 1

using namespace std;

#include <iostream>

#include <ctype.h>

#include <string.h>

#define PW_SIZE (3)

Go()

{

char pw[PW_SIZE];

char specialChars[]="~`@#$%^&*()_-+={}[]|\\:;\"\'<>,.?/";

int nChars = strlen(specialChars);

cout << "Please input the password :>";

cin >> pw;

bool charFlag=false;

bool digitFlag=false;

for (int iLoop=0; iLoop<PW_SIZE; iLoop++)

{

char curChar = pw[iLoop];

if (!digitFlag) { digitFlag = isdigit(curChar); }

if (!charFlag) { charFlag = ispunct(curChar); }

for (int jLoop=0; jLoop<nChars; jLoop++)

{

if (curChar==specialChars[jLoop])

{

if (!charFlag)

{

charFlag=true;

}

} //character is a special char

} //for jLoop

} //for iLoop

if (charFlag && digitFlag)

{

cout << "YES " << endl;

}

else

{

cout << "NO " << endl;

}

}

int main()

{

Go();

}