Convert the following direction into desired one requested in each case.

Question

1.  a) Polar coordinate (3km/h (fraction form), 60^o), convert into both true and quadrant bearing.

b) Scalar component (-5, -10), convert into polar coordinate and true bearing.

Answer 1

(3,60) in polar is (1.5, 1.5sqr3) or about (1.5, 2.6) in scalar coordinates

(-5,-10) in scalar is (10sqr3, 240) in polar or about (17.32,240) or (17.32,4pi/3)

the reference angle is 60 degrees or pi/3, which forms a right triangle with sides in the ratio 1-sqr3-2

(x,y) = (rcos(theta), rsin(theta)) where r=x^2+y^2

and x = rcos(theta), y=rsin(theta)