How many grams of water, H2O, is given off when 62.1g of propane, C3H8 , burns?

Answer 1

Hi Nonya!

Below is the balanced equation for the above reaction.

C₃H₈ (propane) + 5O₂ (oxygen) → 3CO₂ (carbon dioxide) 4H₂O (water)

1 molecue of propnae gives 4 molecules of water.

Now,

convert them into grams.

1 (44 g) of propane gives 4 (18 g ) of water

= 44 g gives 72 g

so if,

44 g gives 72 g

1 g gives 72/44

62.1 g gives 72 / 44 x 62.1

= 101 g

101 g grams of water, H₂O, is given off when 62.1g of propane, C₃H₈ , burns.

Note:

*Its an Unitary method.

*Look at the atomic masses of elements and formula masses of compounds.

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