You are keeping me busy. Please work on your other problems as far as you can and then ask about the step which is causing the most confusion.
The equation you provided is balanced.
Fe2O3 + 3CO(g) → 3CO2(g) + 2Fe(s)
It tells us to expect 3 moles of CO2 per 1 mole of iron oxide (rust)
If we have 201 grams of Fe2O3, we have (201g/159.7 g/mole) = 1.26 moles of the stuff. Three times that means 3.78 moles of CO2. Converting to grams by using the molar mass of carbon dioxide, we arrive at 166 grams of the greenhouse gas.
For extra credit, we need 3.78 moles of CO (105.8 grams) and we produce 252 moles of Fe (140.6 grams). The sum of reactant masses is 306.8 grams and the sum of the product masses is, hold on, . . . 306.8 grams, as per the law of conservation of matter.