Sidney P. answered 04/09/21
Astronomy, Physics, Chemistry, and Math Tutor
a) (0.200 mol C6H12O6 ) * (2 mol CO2 / 1 mol C6H12O6 ) = 0.400 mol CO2.
b) (8.50g C2H5OH) * (1 mol C2H5OH / 46.05g C2H5OH) * (1 mol C6H12O6 / 2 mol C2H5OH) * (180.1g C6H12O6 / 1 mol C6H12O6 ) = 16.6g C6H12O6
c) (8.50g C2H5OH) * (1 mol C2H5OH / 46.05g C2H5OH) * (2 mol CO2 / 2 mol C2H5OH) * (44.0g CO2 / 1 mol CO2 ) = 8.12g CO2