MORE THAN 1 QUESTION

Question

given the formula C7H12+10O2->7Co2+6H2O

1. How many grams of CO2 can be produced from 15g of oxygen?
2. How many grams of carbon dioxide can be produced from 0.455 moles of C7H12?
3. What is th limiting reactant when 10 g C7H12 reacts with 15 g of oxygen

Answer 1

1)

(44.0 g CO₂ / 1 mol CO₂) (7 mol CO₂ / 10 mol O₂) (1 mol O₂ / 32.0 g O₂) (15 g O₂) = 1.44 g = 1.4 g CO₂

2)

(44.0 g CO₂ / 1 mol CO₂) (7 mol CO₂ / 1 mol C₇H₁₂) (0.455 mol C₇H₁₂) = 140 = 1.40 x 10² g CO₂

3)

(1 mol C₇H₁₂ / 96.0 g C₇H₁₂) (10 g C₇H₁₂) = 0.104 mol C₇H₁₂

(1 mol O₂ / 32 g O₂) (15 g O₂) = 0.469 mol O₂

Sine the molar ratio of O₂ to C₇H₁₂ in the reaction is 10:1, we would need (at least) 10 times the moles of O₂ to moles of C₇H₁₂. We (only) have 0.469 : 0.104 or 4.51:1. Therefore, the O₂ is the LR.