Corban E. answered 04/05/21
AP Chemistry Tutor and Former Teacher (Gen Chem, High School chem)
Ka=1.8E-5
1.8E-5=(0.004+x)x / 0.010-x
solve for x
x=[H+]
pH=-log[H+]
Wesley R.
asked 04/05/21Determine the change in pH when 0.004 mol H+ were added to a 0.010M unbuffered acetic acid (chemical formula: HC2H3O2) solution. Assume that the volume of the solution is 1.0L.
Corban E. answered 04/05/21
AP Chemistry Tutor and Former Teacher (Gen Chem, High School chem)
Ka=1.8E-5
1.8E-5=(0.004+x)x / 0.010-x
solve for x
x=[H+]
pH=-log[H+]
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