Finding the produced gas from baking soda and vinegar

Question

I’m trying to understand how to calculate the gas produced (carbon dioxide) when mixing baking soda and vinegar. I have the balanced equation part, but unsure what to do next. I know it will matter how much baking soda I am using but is there a formula?

Answer 1

Use the balanced equation to calculate the #moles of Carbon Dioxide produced.

NaHCO₃ (aq) + HCH₃CO₂(aq) --> H₂O(g) + CO₂(g) + NaCH₃COO(aq)

The following Stoichiometric ratios are produced: NaHCO₃ (aq)/CO₂(g), HCH₃CO₂(aq)/CO₂(g), H₂O(g)/CO₂(g), NaCH₃COO(aq)/CO₂(g)

Example 15 moles of water gives ? moles of carbon dioxide?

15 moles H₂O*(1 mole CO₂/1 mole H₂O) gives 15 moles CO₂

If you want to get the mass of carbon dioxide produced, multiply the moles of carbon dioxide produce by the ratio (molar mass carbon dioxide/1 mole of carbon dioxide).

Answer 2

NaHCO3(s)+HC2H3O2(aq)--> H2O(l)+CO2(g)+NaC2H3O2(aq)

The equation above is balanced, therefore

Determine which you have fewer moles of, HC2H3O2, or NaHCO3.

Since the coefficients are all 1, whichever reactant you have fewer moles of is the limiting reactant.

The limiting reactant determines how much CO2(g) forms.

By the coefficients:

1 mol of NaHCO3 reacts to form 1 mol CO2.

1 mol HC2H3O2 reacts to form 1 mol CO2.

So whichever is the smaller number of moles of reactant is also the number of moles of CO2 that are predicted to form.

For HC2H3O2, you'll probably need to use the molarity. So if it's, say, 0.100 M, or 0.100 molar, that would mean:

0.100 mol HC2H3O2 = 1 L HC2H3O2