% yield of the reaction

Question

If 933g of CO₂ is produced from the combustion of 4.79 moles of pentane with excess O₂ what is the % yield for the reaction?

C₅ H₁₂ (l) + 8O₂(g)--> 5CO₂ (g) + 6H₂O(g)

Answer 1

Calculate the grams expected from stoichiometry:

4.79 moles of P x (5CO₂/1 P) x (Molar mass of CO₂ in g/mole) = g CO₂ theoretical yield

Yield = 100% x (actual yield)/(theoretical yield)

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