CHEMISTRY HELP PLS 20-2

Question

If 10.8 moles of sodium nitrate react with excess iron(III) chloride, how many moles of iron(III) nitrate can theoretically be made?

Answer 1

First, balance the reaction: 3 NaNO₃ + FeCl₃ --> Fe(NO₃)₃ + 3 NaCl.

So 10.8 mol NaNO₃ * (1mol Fe(NO₃)₃ / 3 mol NaNO₃) = 3.6 mol Fe(NO₃)₃.