
Jonah G.
asked 04/01/21How to solve and get the general solution without a calculator
How to solve and then get the general solution of 2 cos2xcos 3pi/10 - 2 sin2xsin 3pi/10 = √2
2 Answers By Expert Tutors

Yefim S. answered 04/01/21
Math Tutor with Experience
2cos(2x + 3π/10) = √2; cos(2x + 3π/10) = √2/2;
2x + 3π/10 = π/4 + 2πn; 2x = π/4 - 3π/10 + 2πn; x = - π/40 + πn or
2x + 3π/10 = 7π/4 + 2πn, 2x = 7π/4 - 3π/10 + 2πn, x = 29π/40 + πn, n = 0, ±1, ±2, ...

Mark M. answered 04/01/21
Mathematics Teacher - NCLB Highly Qualified
sin u cos v - cos u sin v = sin (u - v)
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Mark M.
Post using standard notation.04/01/21