Hello, Gabby,
We need to start with the reaction and developed a balanced equation. I'll presume it is the decomposition of
KClO3 that we are using. I balanced this decomposition reaction:
2KClO3 → 2KCl + 3O2
This tells use we need 2 moles of KClO3 to produce 3 moles of O2, a molar ratio of (2 moles KClO3/3 moles O3). Multiply this ratio by the number of moles O2 desired (3.6 moles O2)
(2 moles KClO3/3 moles O3) (3.6 moles O2) = 2.333 moles KClO3
Bob