Hello, Roberts,
Is the C5H12 in liquid or gas phase? If in liquid, we need to know the density to calculate grams, then moles. If in the gas phase, use the relationship 1 mole gas (at STP) = 22.4liters.
We also need a balanced equation.
C5H12 + 4O2 = CO2 + 6H2O
Once we calculate moles of C5H12, we need to multiply it by 4 to obtain the moles O2 required. Multiply moles O2 by 22.4 L/mole to get volume O2 (at STP).
I assumed the density of C5H12 to be that of pentane, and got 4.2x104 grams pentane. That would be 584.5 moles of pentane. 4 times that will give moles O2 required to burn it all.
I hope this helps,
Bob