boyle’s gas law

Question

100.0 ml at 780.0 mm to standard pressure

Answer 1

Hello, Aubrie,

We can use P1V1/T1 = P2V2/T2 since moles do not change. Rearrange to find V2:

V2 = V1(T2/T1)(P1/P2)

Enter the data. Nothing is said about a temperature change, so we must assume it is constant. (T2/T1) thus simplifies to "1." Standard pressure is 760 mmHg.

V2 = (100ml)*(780mmHg/760 mmHg)

V2 = 102.6 ml

Bob