Find an equation, slope- intercept form, whose graph is a line passing through (5,-7) that is perpendicular to the line 3x-3=4y.

Answer 1

3x-3 =4y, solve for y

y = (3x-3)/4 = 3x/4 - 3/4

slope = 3/4. the slope of a perpendicular line is the negative inverse or -4/3

take 3/4, change the sign from positive to negative and flip the fraction upside down

y=-4x/3 + b, solve for b by plugging in the point (5,-7)

-7 = -4(5)/3 + b

b =-7 + 20/3 = -1/3

y=-4x/3 -1/3 is the perpendicular line through the point (5,-7) in slope intercept form

slope = -4/3, intercept = -1/3