Determine ∆S for the phase change of 1.87 moles of water from solid to liquid at 0°C. (∆H = 6.01 kJ/mol)

Answer 1

As the phase change can be carried out reversibly, ΔS = 6.01 kj/mole / 273 K = 0.022 kj/moleK.

But there is 1.87 moles of H2O, so 0.022 x 1.87 = 0.0411 kj/K = ΔS for the change.