Raymond B. answered 07/30/21
Math, microeconomics or criminal justice
tanB = 5
cotB = 1/5
hypotenuse = square root of 5^2 +1^2 = 26
sinB =5/sqr26
cosB = 1/sqr26
cscB = sqr26/5
secB = sqr26
also add 2npi to each where n= any integer
that's for B in quadrant I
B could be in quadrant III
then put negative signs in front of all the trig functions except cotB
also add 2npi to each where n= any integer