should be: t*5 + (1.2-t)*6 = 7
so t=0.2 for 5m/h, 1hr for 6m/h

Dawson H.
asked 03/25/21Hint: Let t represent the amount of time the athlete jogs at 5 mph. Then 1.2 - t represents the amount of time the athlete jogs at 6 mph.
The athlete jogged _____ hour(s) at a speed of 5 miles per hour and _____ hour(s) at a speed of 6 miles per hour.
should be: t*5 + (1.2-t)*6 = 7
so t=0.2 for 5m/h, 1hr for 6m/h
Nestor R. answered 03/25/21
Statistician with a very good grounding in Algebra
t*5 + (1.2-t)*7 = 7.
t represents time jogging at 5 mph and 1.2-t represents time jogging at 7 mph.
Expand the equation:
5t +8.4 - 7t = 7
-2t +8.4 = 7
Add 2t to both sides and subtract 7 from both sides
8.4 - 7 = 2t
1.4 = 2t
t = 0.7 hr @ 5mph and 1.2-t = 0.5 hr @ 7mph
Check: 5(0.7) + (1.2-.7)*7 = 3.5+3.5 = 7
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Nestor R.
you're right! I don't know how I misread the question!03/25/21