Law of Conservation of Mass problem(NEED HELP)

Question

Given the following reaction, Mg(s) + ZnCl2 (aq) --- > MgCl2 (aq) + Zn (s), how many grams of Zn are produced if you have the following: 45 g of Mg(s) , 300g of ZnCl2 (aq), and 180 g of MgCl2 (aq)

Answer 1

Given the following reaction, Mg(s) + ZnCl2 (aq) --- > MgCl2 (aq) + Zn (s), how many grams of Zn are produced if you have the following: 45 g of Mg(s) , 300g of ZnCl2 (aq), and 180 g of MgCl2 (aq)

Hi Ana,

Here is your answer—

As per the law of conservation of mass, during a chemical reaction mass is conserved, that means that the total mass of all your reactants must be equal to the total mass of all the products.

In this reaction your reactants are 45 g of Mg(s) and 300g of ZnCl₂ (aq) , so total mass of the reactants =345 g

The products are MgCl2 (aq) + Zn (s), mass of MgCl2 = 180 g (given), we have to find the mass of Zn, so let us assign a mass X for Zn

Total mass of Reactants = Total mass of Products

345 g = 180 g + X, So X = 345 - 180 = 165 g of Zn produced