What is the percent yield of phosphorus if 53.6g of calcium phosphate and...

Question

an excess of silicon dioxide yields 6.38g of phosphorus, according to the following chemical reaction?

2Ca3(PO4)2 + 6SiO2 —> 6CaSiO3 + 5O2 + P4

Answer 1

Theoretical yield from 53.6g calcium phosphate: [53.6g Ca₃(PO₄)₂] * [1 mol Ca₃(PO₄)₂ / 310.1g Ca₃(PO₄)₂] * [1 mol P₄ / 2 mol Ca₃(PO₄)₂] * [123.9g P₄ / 1 mol P₄] = 10.71g P₄. Percent yield = 100 * actual / theoretical = 100* 6.38 / 10.71 = 59.6%.