calculate the grams of ZnCl2 that will be produced when 10g of Zn react with excess HCL

Question

calculate the grams of ZnCl2 that will be produced when 10g of Zn react with excess HCL

Answer 1

Zn + 2HCl —-> ZnCl₂ + H₂

Using the balanced equation, there is a one-to-one ratio of the Zn to ZnCl_2.

Calculating the number of moles of Zn in 10 grams:

10 grams of Zn / 65.38 grams/ mole of Zn = 0.153 moles.

Since the ratio is one-to-one, multiply 0.153 moles times the molar mass of ZnCl₂ to yield,

(0.153 moles)(101.83 grams/mole of ZnCl₂) =15.58 grams of ZnCl₂