Calculate the molarity of 121 grams of sucrose, C12H22O11, in 3.10 liters of solution.

Answer 1

First you want to calculate the moles of sucrose. This can be done by dividing the 121g of sucrose by the total atomic mass of 342g/mol (12*12.01+22*1.008+11*16). This gives us 0.353 mol of sucrose. Finally, we can divide that value by the liters of solution. This gives us a molarity of 0.114 M.