question for chemistry

Question

What is the temperature in degrees Celsius of a 0.7 mol sample of argon gas that occupies 3.6 L at a pressure of 1163.9 kPa?

Answer 1

PV=nRT

P=1163.9kPa=11.49 atm

V=3.6 L

n=0.7 mol

R=0.0821 Latm/molK

T=? Kelvin

11.49(3.6)=0.7(0.0821)T

T=719.7 K

K=^oC+273.15

719.7-273.15=446.55^oC