Gravitational potential energy and elastic potential energy.

Question

A coiled spring in a waist trimming exercises requires a force of 54N to compress it by 0.20m. (a.) Find the force constant of the spring. (b.) How much force is needed to compress the spring by o.50m? (c.) What is its potential energy when compressed by 0.5m?

PLEASE HELP!!

Answer 1

F=kx (Hooke's law) thus k=F/x= 54/.2=270 N/m a)

F=kx thus F=270*.5= 135 N b)

PE = .5kx² thus the PE= 33.75 J