
Sidney P. answered 03/23/21
Minored in physics in college, 2 years of recent teaching experience
First, convert rpm to initial angular velocity ωo = (1150 rev/min)*(2π rad/rev)*(1 min/60 s) = 120.4 rad/s.
a) The work will be to cancel out the rotational kinetic energy (1/2) I ω2, where I = (1/2) M R2 for uniform disk. I = (1/2)*(180 kg)*(1.4 m)2 = 176.4; RKE = (1/2)*(176.4)*(120.4)2 = 1,280 kJ, so work = -1,280 kJ.
b) Δt = 4 min = 240s, and use ωf = ωo + α Δt = 0 to find angular acceleration α = -(120.4)/(240) = -0.5018 rad/s2. From τ = Iα, torque = -(176.4)*(0.5018) = -88.5 Nm.
c) Since torque = force*lever arm, magnitude of F = |τ/0.8| = 111 N.
d) Use angular displacement θ = (1/2)*(ωo + ωf) Δt = (1/2)*(120.4 + 0)*(240) = 14,448 radians *(1 rev/2π rad) = 2,299 revolutions.
Chris F.
I really appreciate your help!03/23/21