Hello, Ana,
We need a balanced equation for the decomposition of KClO3. I believe the following works:
2KClO3 = 2KCl + 3O2
The molar ratio of O2 to KClO3 is 3/2. We multiply the number of moles KClO3 times (3/) to find the moles O2 produced.
Bob
To find moles KClO3, divide the mass by it's molar mass (122.6g/mole) to give 0.626 moles. Multiply that by the molar ratio to find the moles O2 produced: (0.062)*(3/2) = 0.939 moles O2.
Robert S.
tutor
Hi, Ana, The calculation is a conversion that changes grams into moles. The molar mass is the conversion factor, which for this compound is 122.6g/mole. This can also be written as 1 mole/122.6 g. In that format, it can be seen that if multiplied by the mass, mass would would cancel, leaving just moles. It is the same, numerically, to the division I did. Looking at just the units: grams/(grams/mole). the grams cancel and moles moves to the top. leaving just moles. -Bob
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03/21/21
ANA CAROLINA F.
Thank you Dr. Robert! Very well explained!
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03/21/21
ANA CAROLINA F.
Hi Dr. Robert, so in this case, my final result is 0.939? I didn't understand this part: divide the mass by it's molar mass (122.6g/mole) to give 0.626 moles.03/21/21