A sample of Kr in a 72.861 L metal cylinder at 128.62 kPa has its temperature changed from 365.42 K to 392.32 K while its volume is simultaneously changed by a piston to 5.765 L. What is the final p

Question

A sample of Kr in a 72.861 L metal cylinder at 128.62 kPa has its temperature changed from 365.42 K to 392.32 K while its volume is simultaneously changed by a piston to 5.765 L. What is the final pressure in kilopascals?

Answer 1

Hello, Brandy,

Please refer to my earlier responses for more details on the steps to take.

In this case we want P2, and so can arrange the equation to:

P2 = P1(V1/V2)(T2/T1)

Enter the data, but convert C to K before entering the temperatures.

We can tell from the ratios in the equation what we'd expect to happen. The problem raises the temperature and also reduces the volume. Both the ratios for V (1/V2) and T (T2/T2) will increase. So we'd expect the pressure to increase dramatically.

Do the calculation. I come up with a number in the range of 1745.2 kPa.

Bob